Chapter Eight The Doppler Effect.
8.1 - Fundamental Principles of the
Doppler Effect. In chapter two, we
considered the special case of zero Doppler effect. This means that the
source was moving in a direction perpendicular to the direction of
propagation of light. The change of frequency due to the Doppler effect
was zero because the radial velocity between the source and the detector
was equal to zero. When there is a relative radial velocity between the
source and the detector, the Doppler effect must be taken into account.
Unfortunately, this phenomenon does not seem to be completely well
understood in physics. There have been many
discussions about the question of the conservation of energy in the
Doppler effect. For example, Weiss and Baez wrote an article [1]
entitled: "Is Energy Conserved in General Relativity?" They consider the case
of the cosmic radiation that has been redshifted over billions of years.
"Each photon gets redder and redder. What happens to this energy?" They
report that:"... the energy is simply lost". Such an answer is not
acceptable since we believe in mass-energy conservation. We do not believe
that any kind of energy can ever be lost whatever the circumstances are.
If this were possible, energy would be created from nothing when an
emitter moves toward an observer because of the Doppler effect.
Of course, an
increasing radial velocity necessarily produces a reddening but one sees
that a reddening is not a proof of a Doppler effect since it can be
produced by other ways. It has been shown [2]
that the reddening of the cosmic radiation can be better explained by a
different phenomenon in which mass-energy is conserved. The reddening
results from the energy lost following numerous interactions of photons on
interstellar gases during billions of years. In that case, the residual
energy is scattered elsewhere so that there is no difficulty to be
compatible with the principle of mass-energy conservation.
8.2 - Mass-Energy Conservation in
the Context of the Doppler Effect. Doppler reddening is a
real phenomenon which can occur in some cases and which is always
compatible with mass-energy conservation. For example, let us consider the
case of a hydrogen atom excited to 10.2 eV (the Lyman state) moving away
from a stationary source. If the hydrogen atom moves at half the velocity
of light, the theory of the Doppler effect (using the wave property of
light) teaches us that we will receive only half of the frequency of the
excited state. This means that the photon received from the moving
particle will have only half the energy of excitation. The question is:
Where does the difference of energy (5.1 eV) go? It has been claimed in
several papers that the energy is missing. The demonstration using
the change of frequency of a wave due to the relative velocity does not
take into account all the energy available in the experiment. Let us
calculate the Doppler effect without using waves but using only the
principle of mass-energy conservation.
8.3 - The Doppler Effect without
Using Waves. Let us consider a mass
mo (at rest) moving away at velocity V with respect to an
observer at rest. Let us assume that the mass is a hydrogen atom. This
moving atom has a total energy of:
 |
8.1 |
Let us consider the
case when that hydrogen atom is excited at the Lyman a atomic state with an energy hno of 10.2 eV. The total energy (potential
plus kinetic) of that excited atom (neglecting the higher order terms)
is:
 |
8.2 |
Let us use the moving
frame of the particle from which the photon is emitted. To be detected in
the rest frame, the photon must be emitted backward (-x axis) from the
moving atom, in the direction of the rest frame where the observer is
located. When the photon is emitted, the atom gets a recoil in the forward
(+x axis) direction giving it an increase of velocity Dv. Of course, the total change of momentum DP of the moving system (photon plus atom) is zero. At
the moment of emission, considering the photon's momentum, we have:
 |
8.3 |
or
 |
8.4 |
With respect to the
rest frame, the velocity of the hydrogen atom was V before the emission of
the photon. After the emission of the photon, the final velocity
Vf of the atom with respect to the rest frame becomes:
Equation 8.4 in 8.5
gives:
 |
8.6 |
The total (mass plus
kinetic) energy of the de-excited hydrogen atom after the emission of the
photons is (neglecting the higher order terms):
 |
8.7 |
Using equation 8.6
gives:
 |
8.8 |
The change of kinetic
energy of the hydrogen atom due to the recoil of the photon is:
 |
8.9 |
From equations 8.8 and
8.1, neglecting the second order, we have:
 |
8.10 |
 |
8.11 |
Equation 8.11 gives the
increase of kinetic energy of the atom due to its recoil. According to the
mass-energy conservation principle, the increase of kinetic energy of the
atom must come from the photon energy. Since the excitation energy
initially available was hno, and since
equation 8.11 gives the energy transferred to the atom (as kinetic
energy), the residual photon energy hnf is:
 |
8.12 |
which is:
 |
8.13 |
Equation 8.13 is
exactly identical to the Doppler equation. We have demonstrated
the Doppler equation using no wave model but only mass-energy
conservation. The energy apparently lost in the Doppler phenomenon is
simply transferred as kinetic energy to the emitting atom whose velocity
has increased due to the recoil momentum. It is also important to notice
that the amount of kinetic energy lost in equation 8.11 is independent of
the mass of the particle. The above demonstration
solves the problem discussed by Weiss and Baez and others. We conclude
that the energy redshifted by the Doppler mechanism is not lost. It is
simply transmitted as kinetic energy to the emitting atom due to recoil at
the moment of emission. We must notice that this explanation has nothing
to do with relativity.
8.4 -
References. [1]
http://www-hpcc.astro.washington.edu/mirrors/physicsfaq/energy_gr.html
[2] P. Marmet, A New
Non-Doppler Redshift, Physics Essays, 1, 1, P. 24-32,
1988.
8.5 - Symbols and
Variables.
EV |
energy of a mass mo moving at velocity
V |
E*V |
energy of a mass mo moving at velocity
V and excited to 10.2 eV |
E'V |
energy of a mass mo moving at velocity
V after losing its energy of excitation |
no |
frequency corresponding to the excitation
energy |
nf |
frequency emitted by the
atom |
|